3x*2x=14^2

Solution for 3x*2x=14^2 equation:

3x*2x=14^2

We move all terms to the left:

3x*2x-(14^2)=0

We add all the numbers together, and all the variables

3x*2x-196=0

Wy multiply elements

6x^2-196=0

a = 6; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·6·(-196)
Δ = 4704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4704}=\sqrt{784*6}=\sqrt{784}*\sqrt{6}=28\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{6}}{2*6}=\frac{0-28\sqrt{6}}{12}
=-\frac{28\sqrt{6}}{12}
=-\frac{7\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{6}}{2*6}=\frac{0+28\sqrt{6}}{12}
=\frac{28\sqrt{6}}{12}
=\frac{7\sqrt{6}}{3}
$